Diptee1211

M. Loisel solved his problem by advising her to request her friend, Mme Forestier to lend her some jewels. Accordingly, she went to Mme Forestier and borrowed a diamond necklace for the occassion.

Given: Triangle ABC and ∆PQR in which AD and PM are medians drawn on sides BC and QR respectively. It is given thatTo Prove : ∆ABC ~ ∆PQRConst : Produce AD to E such that AD = DE and PM to F such that PM = MF.
Proof : In ∆ABD and ∆CDE,AD = DE    [by construction]∠ADB = ∠CDE[vertically opposite angles]and    BD = DC    [AD is a median]Therefore, by using SAS congruent condition                                   [by CPCT]Similarly, we can prove                                                [by CPCT]It is given that:              Therefore, by using SSS congruent condition                    

A black homozygous male is mated with a white homozygous female to give F1 generation. If the progeny in F1 generation has all black dogs then we can conclude that the dominant coat colour is black.              BB × bb



 
b
b


B
Bb (black)
Bb (black)


B
Bb (black)
Bb (black)