Diptee1211

A black homozygous male is mated with a white homozygous female to give F1 generation. If the progeny in F1 generation has all black dogs then we can conclude that the dominant coat colour is black.              BB × bb



 
b
b


B
Bb (black)
Bb (black)


B
Bb (black)
Bb (black)

Given: Triangle ABC and ∆PQR in which AD and PM are medians drawn on sides BC and QR respectively. It is given thatTo Prove : ∆ABC ~ ∆PQRConst : Produce AD to E such that AD = DE and PM to F such that PM = MF.
Proof : In ∆ABD and ∆CDE,AD = DE    [by construction]∠ADB = ∠CDE[vertically opposite angles]and    BD = DC    [AD is a median]Therefore, by using SAS congruent condition                                   [by CPCT]Similarly, we can prove                                                [by CPCT]It is given that:              Therefore, by using SSS congruent condition                    

M. Loisel solved his problem by advising her to request her friend, Mme Forestier to lend her some jewels. Accordingly, she went to Mme Forestier and borrowed a diamond necklace for the occassion.